In triangle ABC, with AB = 3 and BC = 4, what is the cosine of angle C?

To determine the cosine of angle C in triangle ABC, we can use the law of cosines, which states that for any triangle with sides a, b, and c opposite to angles A, B, and C respectively, the formula is:

[ c^2 = a^2 + b^2 - 2ab \cdot \cos(C) ]

In the context of triangle ABC, let's assign the side lengths: AB is assigned as side c, BC as side a, and AC as side b. Given that AB = 3 (c = 3) and BC = 4 (a = 4), we need to identify the length of AC (b) in order to apply the law of cosines. However, without the length of side AC, we can still find the cosine of angle C by recognizing a potential right triangle.

We can use the Pythagorean theorem (if applicable) to deduce a possible triangle configuration. Assume triangle ABC is a right triangle, we can hypothesize that the third side AC can be found if it satisfies the condition of a right triangle where:

[ b^2 + a^2 = c^2 ]

However, since we lack the direct value of b