If the perimeter of a field is 300 yards and the length is twice its width, what is the width?

To find the correct width, we start by letting the width of the field be represented by ( w ). Since the length is twice the width, we can express the length as ( 2w ).

The formula for the perimeter ( P ) of a rectangle is given by:

[

P = 2(\text{length} + \text{width})

]

Substituting the expressions for length and width into the formula gives:

[

300 = 2(2w + w)

]

This can be simplified:

[

300 = 2(3w)

]

[

300 = 6w

]

To find ( w ), divide both sides by 6:

[

w = \frac{300}{6} = 50

]

This calculation indicates that the width of the field is 50 yards.

Utilizing this width, the corresponding length can be calculated as:

[

\text{length} = 2w = 2 \times 50 = 100 \text{ yards}

]

The perimeter can be verified by substituting the width and length back into the perimeter formula:

[

P = 2(100 + 50) = 2