Consider the following numbers: the square root of 2, pi, the square root of 25, the cube root of 8. How many of these numbers are integers?

To determine how many of the given numbers are integers, let’s evaluate each one:

1. The square root of 2 is an irrational number. It cannot be expressed as a fraction of two integers, so it is not an integer.

2. Pi (π) is also an irrational number. It is a non-repeating, non-terminating decimal and does not qualify as an integer.

3. The square root of 25 is a perfect square. Since 25 is 5 multiplied by itself (5 x 5 = 25), the square root of 25 equals 5, which is indeed an integer.

4. The cube root of 8 is calculated as the number which, when multiplied by itself three times results in 8. Since 2 x 2 x 2 = 8, the cube root of 8 is 2, which is also an integer.

From the evaluation, we find that the square root of 25 yields one integer (5) and the cube root of 8 yields another integer (2). Therefore, there are a total of two integers among the given numbers. This confirms that the correct response is justified as being two integers.